CLASS 11 | ONE SHOT | Thermodynamics | Physics | NEET 2024 | Xylem NEET Tamil

hi hello wome and welcome back to channel physics the one shot series with me your sh m'am you people know when shy m' is here no you're right yes exactly best and the best best of best because thams best way okay okay so let's begin with our one short today top thermodynamics as per4 okay okay without any heat in motion theory of gases of gas because that is going to be the basic okay so let's begin in the topics patient patient okay so let's start with your zero law of thermodynamics so zero equ ofat heat flow okay proper okay the example is going to be the ceramic okay norals okay object okay so this is how you have to learn your first zero law okay thermodynamics important terms which ISAT which is very important okay right because energy can be created neither be destroyed right Dy exct given extracted so system system heat okay heat is nothing but Q so be careful be careful be careful okay okay now let's go for the next important parameter which is internal energy ktic theory of gases systemer whatever it may 100% efficiency 100% efficienc okay the system the system okay for example okay this is an example so internaly okay so this is how you have to analyze the internal energy and internal energy energy energy 100% energyy because ktic theory of gases because gas MO maoc is very maximum okay freedom because yes or no it has its own freedom of freedom right P equal equal internal enery change internal energy 2 change in pressure and and volume phys so change in press volume okay and now work done so the next important parameter because 2019 but it's a very very easy question okay work will be written as integral of P DV so volume initial to the volume fin okay okay so constant pressure change in volume okay constant pressure volum pressure will be constant always pressure is constant gas is expanding physics teacher phys gas so gas is expanding work done by the gas is positive over here gas work done by the gas by the gas by the gas so work done by the gas is environment work surrounding surrounding work will be work by the system work by the Sy the gas okay by the system okay so work done by the gas that is positive which means volum increase volum increas gas gas this is okay so volume is decreasing vol work will be work will be negative okay so gas okay okay now let's talk about the formula Di so work is equal PV okay equal toal of P DV V initi will be the work done will be the work that means gas is exping gas is expanding gas gas so in the work will be positive in the work done will be positive and that is going to be the gas on the gas decrease negative okay important okay so area under the P pressure volume done so the next important concept is first law of thermodynamics okay first law of thermodynamics the first law of thody okay because frac so the internal energy is important first law of thermodynamics okay Q heat provided heat in the system heat given okay Q is equal to change in internal energy plus work done okay this is going to be your first law of thermodynamics internal inter because it is going to be a very helpful thing for example heat has flown into the system heat work done on the system work done on the gas work done on the gas qal plusus W on the system on the systemus work on the system isre so work done on the system wal so what happens now right is increasing is increasing qre Q increasing okay so work on the gas heat flow into the system work onow into decrease Q is decreasing okay unworked and will be negative unworked and will be negative compr either expansion work done by the system qal plus okay so by the system inre okay work by the system so expansion we could find okay okay so let's move further okay scr okay and please please please once the one to make it very very easy for you okay so now thermodynamic parameters or variables so thermodynamics fun function State function function State function path function so that means process heat given internal energy work okay State functions or state state function state starting finishing so State function starting initi starting point final okay so initial value starting and ending point same starting and ending point same and in the starting and ending point is going to be your path independent so this is called so it will only depend on the initial and final Point initial and final State ini State function okay initial and final Point initial and final okay will be talking about internal energy so internal energy it is your state function okay so internal energy function so State function so1 is equal to2 and final points are the same okay FAL enery therefore it's nothing to do with the pathy the travel energy internal energy travel starting and initial point okay so internal energy will be called function qal + Rus w function State fun so Q is directly proportional to function function so path function is nothing but work me soat f okay function okay will be second which means q1 is greater than Q2 q1 is greater than Q2 okay State function function then is also your path function work then and Q will be path function and internal energy State function okay so this is what we have discussed discuss so Q is also a path function done now let us talk about constant con PV Okay so Q is equal to Q formula will be nothing but Plus work done okay isocoric process isocoric isocoric so ISE Conant okay pval okay volum Conant p is directly proportional to The Temper volum okay so volume contion sorry volume constant finus V initial volume con okay next qal qal to+ W heat will be equal to internal heat will be equal to very very simple will converted into internal energy okay internal what is your internal energy soal F / 2 into P formul okay internal energy so this is your internal energy Formula F degree of freedom okay is nothing but degree of Freedom mon because work will be zero so now let's talk about the graph okay disc one is press temper volume will be constant volume will be constant is increasing in pressure okay it is increasing in pressure so volume will be again constant and decreasing in pressure decreasing in pressure supp for example volum will be con okay so this is your isic okay this is your isocoric clear AR and this is going to be the final shot okay it will be converted into internal energy it will be converted into internal energy and now isobaric process isobaric bar pressure is going to be the constant one pval so pressure constant Conant V is directly proportional to the temperature V is directly proportional to the temperature p nothing but your internal pressure I mean volume okay and intern is nothing but DW equal DW equal p into DV okay P constant will never be equal to increase the temperature by same amount to increase the internal energy by the same amount more heat should be provided in the isobaric process so more heat should be given because qal plus W so so Q is increasing we have to give lot of so we have to give a lot of inut us talk Q okay qal so that is work done is nothing but P into v p into V we people know PV will be equal to NR into Okay so so this is going to be your internal energy and your Q okay internal energy this is your internal eny so which means Q is increasing Q is increasing we have given L of so that is your will be a straight line the next one is pressure tempure that will be a constant and pressure volume volum decre that is your isic compression and volum increas your because work done is zero volume is constant and work done completely depends on your volume work is to internal energy is 1 1 2 1 by 2 + one 1 is to F by 2 is to F by 2 + 1 so ratio okay 3ree of freedom andree of Freedom andom polyatomic so polyatomic okay polyatomic it will 1 is 3 is 4 okay so nonlinear polyic okay linear polyatomic is a nonlinear polyatomic okay process okay so now the next process is ismal process isal that is your temper temperature is constant so temperature is constant p v Al so PV is constant which means pressure and pressure is inversely proportional to the volume pressure is inversely proportional to the volume and inversely proportional inverse rectang q q is nothing but Plus work done right f/ 2 N right so log NR Ln into V final minus V initial volume final minus volume initial and internal energy does not vary internal energy does not vary because the whole so that means pressure and volume are inversely proportional right constant Andre this is ismal expion com is Conant both are constant both are constant volume con temperature constant and finally this is your output ismal process which is W is equal to Q is equal to n r correct n RT VF minus v p initial V initial P final V final okay so you can write whatever you want okay so now the last process is your process pressure volume con so Q is going to be the constant con constant Q is constant du + W is equal to constant is equal to you people have to learn a new thing so listen in thetic process heat exchange Q so heat exchange will be zero du plus d this is going to be the equ finally you will be getting DP by DV the change in pressure divided by the change in volume F / 2 + 1 / f by 2 into PV and the whole so DP by dval minus gamma into DV P by V so that means dpv DT slope one dimension motion two Dimension okay don't take it light this is going to be your equation okay change in pressure divided by the change in volume will be equal to okay p v power gamma is equal to constant p v power GMA is equal to constant G so that will be constant that will be constant okay so finally work will be negative to the internal energy because q w q alus W right walus yes or no nrt into DT / 1us GMA and change in pressure volume divid 1us GMA G already F by 2 + 1id if the gas expand if the gas expands the work done by the gas at the cost of its internal energy so internal energy will be equal to the work which will be p is inversely proportional to V power G AA we will be getting a inverse graph Okay so volume increase this is your adiabatic expansion volume decrease compression this is going to be your compression okay Bar Seven okay so what you people can do butash if you people are thinking thermodynamics is easy peasy lemon squeezy okay so now which is specific heat capacity okay specific heat capacity already specific heat specific heat one g of sub heat capacity Okay C CP specific heat capacity at constant pressure C specific heat capacity with constant volume with constant volume okay so now smaller specific heat capacity Q isal NCT formula changes DQ is equal to NC into DT okay and DQ / d c specific heat capacity okay number of moles DT change in temperature okay change okay this is major major major major important and now let us talk about specificity see listen equal to Du + DW yes or no du + DW NC and DQ is equal okay F by 2 NR into DT yes or no F by DT yes [Music] DT F into r so fin DQ so this is for your isocoric process is sorry ISO isobaric process for examp DQ formula DQ formula is nothing but n n r into f/ 2 + 1 into DT okay capacity and okay expression process 2 okay/ 2+ 1 into R okay and is is temperature will be changing temp will be zero is infity okay change in temperature is zero okay so we can find only for isor and isic is will be Z this is very very important okay very very very very important and cus cpal 1 into rabatic zero isothermal Infinity so CP minus CV equal r c and now polytropic process po Tropic process coop process that means volume is constant volaric process pressure will be constant okay and isothermal process temp will be constant because was constant over here okay G formulas so change in temperature divid by 1 byx x polytropic coefficient okay so polytropic coefficient and/ 2 1 / 1 - x f / 2 + 1 / 1 - x poop okay these are really important I have to I have to identify what is the molar specific heat capacity now M specific M specific capacity so f r / 2 + r / 1 by 1 minus X okay inst me hash willo okay so now let's talk about the so we will be looking into it okay poop expression DP dval p vop okay andus P that is going to be your adiabatic process that is going to be your adiabatic process will be straight L okay so ismal okay so btp a I okay so BTS btp btp okay St stra okay so BTS btp a b okay okay expansion is isal is expansion so BP B P okay right so is greater than isothermal is greater than process okay so isic okay okay BP okay so compression steeper than okay clear so these are your graphs in the okay so now let us compare one more important thing buk modul with gas mod because modul is equal to change in pressure change in volume so buk modulus can be written as gas buk modulus can be written as coefficient of polytropic process into pressure polytropic pressure into polytropic coefficient into pressure poop Presse that is your isothermal G gtic process okay okay so these are much much much much more important process okay process next one is cyclic process the next one is cyc process Cy process starting and ending point will be the same okay I mean volum volume constant volume const starting and final Point are the same process one to the expansion and the expans work is positive so work done is positive and work done is greater compression compression 2 Vol will discussing okay the complete work is and internal energy is equal to Z because internal energy a state function State fun initial and starting point initial and starting point are the same so internal energy is zero change in internal energy will be zero qal to+ w q equal to positive W and Q is positive Q positive heat is given okay Q is positive Q is positive so Q is positive system gains Energy System you have to study your comparatively and now the next thing is law of second law of thermodynamics the second law of Thermodynamics the second law of Thermodynamics that is statement so % heat input 100% Q 100% work for examp Sorry q1 by Q2 right so 1 minus T1 minus T2 T2 minus T1 sorry T2 minus T1 Q2 minus q1 okay ler heat FL we have to do some work that means so that means we have to give some external work so we have to do some external work okay soams so that's it that's it updated so let's start your pyq okay so first question 20 ideal gas under goes four different process from the initial State as shown in the figure below okay those process are adiabatic isothermal isor isobaric and isor okay name the curve which represents the adiabatic process from one 1 2 3 and four processess process because yellow statement that is the ismal so two is your perfect answer so perfect answer perfect answer right now the next question the PT graph for an ideal gas expression in the in a piston cylinder assembly piston cylinder assembly okay normal pist process shown in the figure the processes so so that means pressure is constant that means process everything is easy okay yes so that's it for the dayam please please again take some time and this is going to be a homework question 2019 so that means the type of questions okay thank you so much for your perance and until then it's me your shy maam you people know when shy m is here know if you're right so next stay happy do hard work okay bye everyone take care

Channel: Xylem NEET Tamil

Views: 39,585

Keywords: electromagnetic induction class 12, physics, electromagnetic induction, magnetic flux, class 12 physics, class 12 physics chapter 1, class 12 physics one shot, class 12, physics class 12, neet 2024, neet, physics wallah, pw, chemistry, competition wallah, neet motivation, biology, arjuna neet, aiims delhi, xylem sslc, xylem plus one, xylem, plus one, physics for beginners, plus one class, plus one class eduport, plus one physics, plus one arabic class, Xylem Neet Tamil

Id: b-1VaGWgdlQ

Length: 87min 44sec (5264 seconds)

Published: Wed Dec 13 2023