11.9.3 Packet Tracer - VLSM Design and Implementation Practice

vlsm design and implementation practice the topology this [Music] one two three four five five subnets or five networks the addressing table that you need to complete this addressing table examine network requirements determine the number of subnets needed okay [Music] you will submit the network address 192.168.72 prefix 24 the network has the following requirements switch one long seven hosts ib addresses this switch to lang will require 15 host ip addresses this is the network of switch 2. switch 3 will require 29 host ip addresses this network and switch 4 long will require 58 host ip houses this network and don't forget this the the link between routers this serial connection is the fifth network or fifth subnet how many subnets are needed in the topology five one two 3 4 5 determine the subnet mask information for each subnet which subnet mask will accommodate the number of ip addresses required for switch one okay for this network the network of switch one with seven hosts okay i know for seven holes you will you will use the following subnet mask okay this is the subnet mask in binary is the prefix 28 because you have 28 ones here and four zeros here the this is the network portion and this is the host portion so the prefix is 28 and on decimal is 255 to divide it by 240 okay and do the following calculation count the number of bits on host portion four bits 2 is the base for binary system power [Music] power 4 minus 2 14 hosts okay will require 14 hosts okay this this subnet mask will support 14 hosts maximum 14 hosts and 14 host is a good number for this network for seven hosts anyway what happens if i will do the following i will use [Music] profix 29 this is 240a okay what happened if i will choose this this is uh 29 ones on network portion three zeros on the host portion this is prefix 29 on decimal is 248 okay two is the base for binary system and power of three three bits in the host portion minus two this is six six hosts and six hosts are not enough for seven hosts okay okay very good and what happened if i will choose 27 27 on decimal is 224 okay [Music] 27 ones on the network portion five zeros on the horse portion the prefix is 27 decimal 224 is two power of uh five bits on the host portion two power five minus two theory costs through the hosts okay uh 27 prefix will support theory the hosts and thirdly host will support the requirements on the network of switch one the requirement of seven costs but you are wasting ip addresses so that's why the elsewhere is this 14 hosts is the best number in this case okay and which subnet mask will accommodate the number of ip addresses required for the network of switch one the answer is this on decimal on prefix or on binary how many usable cost addresses will this net support 14 hosts okay next which subnet mask will accommodate the number of ip addresses required for the network of switch to switch switch to 15 hosts okay i will use 27 prefix that is 224 obviously 28 prefix supports maximum 14 horse and 28 is not enough so that's why i'm using 27 the next number is this in binary and decimal 224 and will support two power uh five bits in the host portion minus two thirty costs okay very good this is a good number for the network of switch two and the answer is this net mass 27 prefix or 224 how many usable host addresses will this subnet support and fill the costs and now the same procedure for the network of switch 3 with 29 hosts okay 29 hosts and also 27 is a good number also 27 is a good number because uh 27 prefix will support 30 costs and is enough for 20 hosts required on the network of switch 3. so this is the answer which subnet mask will accommodate and for the network of switch 3 subnet mask 27 224 how many usable host addresses will the subnet support theory hosts okay now for the network of switch 4 58 hosts 58 you can use this 26 26 on decimal is 192. okay i will choose 26 prefix with 26 ones in the network portion six heroes on the horse portion two power six okay six zeros on the host portion two power six minus two sixty two hosts 62 horse and 60 to host is a good number for 58 horse very good so which blend mass will accommodate for the network of switch 4 26 prefix or 192 how many usable hosts addresses will sub will this subnet support 62 cost which subnet mask will accommodate the number of ips required for the connection between remote side one and remote site ii okay this link this hero connection here you only need two hosts because it's a point-to-point connection you need only two hosts and the number for this and the subnet mask for this is this the following is theory the prefixes theory and decimal is 252. we support two hosts okay and 30 ones in the network portion two zeros on the host portion prefix theory on decimal 252 okay and 2 power 2 minus 2 is 2. so that's why we'll support two hosts and the answer is uh subnet mask 2 divided b divided by 85 252 or prefix theory and will support two hosts okay and now design the blsm addressing scheme blsm stands for variable length subnet mask variable length subnet mask and open this file my spreadsheet what is the base ip address is this uh 182 1687 it do 0 24 182 168 72 0 24. okay the base ip address and these are the network requirements start with the highest number of hosts and what is this 58 hosts the network with the highest number of hosts the largest network 58 hosts [Music] this is the network of switch 4 with 58 hosts okay the next is the next largest number is 29 switch 3 network switch 3 network with 29 hosts the next is switch to 15 hosts switch to 15 hosts the next is switch one seven hosts switch one seven hosts and don't forget the serial this network the point-to-point network with two hosts between remote site one remote side two the connection between remote side one and remote side two with two hosts okay and first this number convert this number to binary the base the base ip address 180 1 68 72 0 to binary here okay it's not necessary to convert all the octets to binary i will convert only the last two octets okay so 182 on decimal 168 on decimal 72 on binary and 72 is uh 64 plus 8 is 72 so is 0 1 0 0 1 0 0 0 okay this is 72 okay and the next number is zero zero in binary zero zero zero zero zero zero okay 192 168 72 0 and now you need 58 hosts and here on the number of hosts search a good number for 58 theory is not enough 62 is a good number and so you need to so this will be the subnet mask okay 62 is a good number for 58 hosts so this will be the subnet mask and now you have the network and subnet mask or the subnet and the subnet mask and now this is the network address or subnet address and the subnet mask so the network is 182 168 72 0. 168 72 0 and the prefix is this and that prefixes this is 26 8 bits plus a bit 16 bits plus 8 bits 24 bits 25 26 26 bits and now do the following copy this and fill the remaining spaces with ones and now this is the broadcast address 182 168 72 182 168 72 and this number is 63 this is 63 okay 63 or if this is 64 this is 63 okay this number is 63 and 63 and the same prefix 26 and the first ip host on this subnet is one next to the network 180 168 721 26 and the last ip host is one before the broadcast 180 1 68 to 60 to 26 ready go to the next number with the network of switch 3 with 29 hosts okay but what is the next number of this binary number okay the next is the following 182 168 zero one zero zero one zero zero zero and if you have six ones on binary if you have six ones on binary the next number in binary is one followed by six euros okay if you have six ones in binary system the next number in binary is one followed by six heroes and this is the next number and search a good number for 29 hosts search a good subnet mask for 29 house and use this this theory so the subnet mask will be this okay theory is a good number so the subnet mask will be this and this is the network address is 182.168.72 64. 182 168 72 64. okay look at this this one and 64. and the prefix is 27 8 plus 8 16 plus 8 24 25 26 27 okay and also you can verify if the broadcast of the previous subnet is 63 the network address of the next subnet it will be 64. so this is very good okay now you have the network address and copy this fill the remaining spaces with ones and this is the broadcast hours 192.168. 72. when i do 168 1 168 72 and this number is 64 plus 31 64 plus 31. is 95 64 plus 31 is 95 and prefix 27. okay 27 is the prefix so the first half the first host is one next to the network 182 168 72 65 prefix 27 and last ip one before the broadcast 182 168 72 94 prefix 27 okay 94 one before the broadcast okay very nice and what is the next number in binary of this will be 182 168 zero one zero zero one zero zero zero zero one if you have five ones in binary system the next number of this is one followed by five zeros if you have five ones on binary the next number in binary is one followed by five zeros and 15 hosts search a good subnet mask for 15 14 is not enough theory is very good is this this is the subnet mask and this is the network address 182 168 72 and this is uh 64 plus 32 is 96 and the prefix is 27 again and don't worry about this 27 again okay and 24 25 36 27 and copy this fill the remaining spaces with ones and this is the broadcast address the broadcast address will be 182 168 72 this number is 127. if this is 28 this is 127. 127 prefix the same prefix 27 and the first ip one next to the network 192 168 72 97 prefix 27 [Music] last ip 192 168 72 one before the brother that's 126 prefix 27 okay the next number of this 192.168 zero one zero zero one zero zero zero the next number of uh seven the next number of uh seven ones in binary is one followed by seven zeros and the requirement is seven costs and six is not enough use 14 so the subnet mask will be this and this prefix is 28 25 26 27 28. so the network address will be 182 168 72 128 182 168 72 128 prefix 28 25 26 27 28 okay okay and copy this fill the remaining spaces with ones the broadcast will be 192.168.72 this number is 28 plus 15 okay 128 plus 15 is 143 143 prefix 28 the same prefix okay the first ip 182 168 72 129 prefix 28 last ip 182 168 72 prefix 142 prefix 28 okay and finally two hosts for the point point link the next number is 192.168. co1 clco120 in binary the next number of four ones is one followed by four zeros two hots here so this is the new subnet mask so the network address is 182.168. uh 72 28 plus uh 16 is 144 when i two and 68 72 144 prefix theory okay 25 26 27 28 29 30 or [Music] yeah this is the network address copy this fill the remaining spaces with ones this number is [Music] 147 18 168 72 147 prefix theory okay is 144 plus three is 147. the first type 181 68 72 145 prefix 30 k1 next to the network and the last the second and last ip okay the second and last ip host is 182 168 72 146 prefix theory very good my table is ready okay use the first subreddit to accommodate the largest slang the second largest the third largest okay this is the order from the largest okay first the the largest number of calls the second largest number of costs and so on so this is ready and this table is this okay so this table is ready and don't worry about it and document the addressing scheme okay for this copy the addressing table copy this ctrl c open a microsoft word document or any text processor and paste okay remove the format of the table okay remove the format do the following okay very good and now assign the first usable ip addresses to remote taiwan for the two long links and the one link okay so remoteside1 router will have the first ip addresses on these three subnets the first ip on this interface for subnet of switch 2 the first ip for the for this interface on the subnet of sichuan and the first ip this interface for this point-to-point link okay and okay and now configure gigabit zero zero on remote side one router this is a gigabit zero zero on remote side one router and this is gigabit zero one gigabit zero one refers to the port on the switch but on the router side is gigabit zero zero because this is gigabit zero one okay and okay this is gigabit zero zero is the subnet of switch one the subnet of switch one is this and use the first type okay copy is this 129 and use for four gigabit zero zero and the subnet mask is this 28 28 in decimal is 255 to 40. now you have zero one is the another side this gigabit zero one is the network of switch two network of switch two is this and select the first ip host is 97 with prefix 27 the first ip 97 prefix 27 is 2555 285 234 and serial 000 this is this is serial 0 0 is this this subnet the point point link select the first ip 145 prefix 3d 145 prefix field is 2 divided between 35 to 52 okay now go with remote side 2 assign the first usable ip access to remote site to router for the two lounge links assign the last usable ip address for the one link okay for these two subnets the lungs use the first ip on remote high to router the first ip on here the first ip here but on the serial link on the point point link use the second the second ip or or the last okay assign the last usable ip address for the one link okay on remote side to router use the last ip address on on for this interface the last okay and first gigabit zero zero this is gigabit zero zero on the router this is this should be gigabit zero one this is gigabit zero zero the network of switch three the network of switch 3 use the fields ip copy and 65 with prefix 27 65 prefix 27 is 224 for gigabit zero one this side is the network of switch four is this and the first ip is one copy prefix 26 gigabit zero one is number one prefix 26 is 255.35 192. finally the serial interface for serial 0 use the last ip for this point point link use the last ip host that is also the second host the last and second 146 copy prefix field paste one for this prefixes subnet mask is 255 to 52 and assign the second usable ip address for the switches okay the second obviously the second ip on the network okay for for example for switch one in the network of switch one use the second ip for the switch okay for switch one if the first is 129 the second will be 130 prefix 28 okay for switch one if the first is 20 129 second is 130 okay prefix 28 28 is 240 and the default gateway is [Music] for switch one the default gateway is the the [Music] the gigabit zero zero on the router remote taiwan the default way is gigabit zero zero on the router remote taiwan gigabit zero zero remote taiwan this is the default way for switch one okay for switch two for switch 2 the first is 97 prefix 27 the second will be a 98 and prefix 27 is 224 and for switch 2 the default gateway is gigabit 0 1 on the router gigabit zero one on the router this is the default gateway switch three the first is 65 prefix 27 so the second will be 66 prefix 27 is 224 and obviously you know for switch 3 the default gateway is gigabit gigabit 0 0 on on the second router second router gigabit zero zero 65 in switch four the first is 1 prefix 26 so the second will be 2 and 26 is 182 and obviously this is the default gateway it's number one okay and assign the last usable ip addresses to the hosts okay and user one is placed on network of switch one and assign the last ip okay user1 is placed on switch one network and use this the last ip is 142 prefix 28 user 1 ip 1 142 prefix 28 is 240 the default gateway is just the the interface of gigabit uh [Music] gigabit zero zero on remote taiwan gigabit zero zero on remotes i want this is the default gateway 139 obviously the the default way will be 129. okay for user 2 that is user 2 is placed on switch 2 network this is the last ip126 prefix 27 user 2 126 province prefix 27 is 224 and first ip is [Music] obviously this knight d7 okay is placed on the same network in 97 the third type is the default way in this case user 3 place it on switch 3 and network last ip is 94 prefix 27 user 3 knight before prefix 27 is 224 and for user three the default is gigabit zero zero on the second router gigabit zero zero on the second router is 65 finally user four user four is placed on switch for network use the last ip that's it that is 62 and the prefix is 26 62 the prefix 26 is 192. obviously this is the default gateway one okay and in the same network the first ip okay table is completed assign ib addresses to the devices and verify connectivity most of the ip addressing is already configured on this network implement the following steps to complete the addressing configuration [Music] complete ip addressing on remotes i1 router lan interfaces okay so complete on this router only on long interfaces okay click on remotes i1 enter enable show running config to verify enter space space serial interface already assigned it is 145 145 very good but you need to configure gigabit zero zero and gigabit zero one okay so use the table configure these two interfaces configure terminal interface 0.800 ip address 192 168 72 129 285 35 240 okay and enter no shutdown okay and gigabit zero one ip address is 97 subnet mask 224 enter not shut down okay these two configurations configure ip addressing on switch 3 including the default gateway ok access switch 3. and this is the configuration enter enable configure terminal configure on interface milan one interface one ip address 180 168 72 it's 66 prefix and 224 66 to be divided by 255 224 shut down exit ip default dash get way 192 168 72 65 very nice and configure ip addressing for user for including the default gateway okay access user for ipconfiguration and set this configuration 192.168.72 62 subnet mask is 192. default by the way 182.168.72 one okay you got 100 but the important thing is to verify the connectivity okay you can only verify connectivity from remote side one to switch three and user four okay you don't you don't have access to user one for example it's locked user two logged user three logged only for router one switch three and user four i will use user for and go to command prompt you should be able to pick every ip address listed in the addressing table okay [Music] pink to user one pair 182 168 72 142 success user 2 is 126. success user 3 is 94 very good user 4 is itself switch 1 is 130 success you can repeat [Music] switch 2 is 98 success repeat okay switch 366. success repeat switch four is two success and also you can pick the interfaces on the routers and will be successful go to remotes i1 length show running config enter space space look at this configuration of eigrp is a dynamic routing configured that will permit the connectivity between all devices eigrp is configured on remotes i1 also configured on remotes i2 routers so [Music] this dynamic routing protocol will permit the connectivity between all subnets without this configuration the connectivity will be only available between directly connected networks in the router okay for example without this configuration user 1 will be able to ping user 2. but will not be able to pin user 4 or user 3 because this router only knows these three networks one two three thank you very much you

Channel: Christian Augusto Romero Goyzueta

Views: 22,136

Keywords: cisco, itn, introduction to networks, v7.0, version 7.0, version 7, ipv4, addressing, subnets, subnetting, addressing scheme, vslm

Id: RahxSG7j4LI

Length: 53min 13sec (3193 seconds)

Published: Thu Apr 28 2022