MOLE CONCEPT, ATOMIC STRUCTURE, PERIODIC TABLE In 1 Shot | WBJEE Revision

hello students welcome to PW bang AUD video hell hello hello audio video C good afternoon hello showman sonal Rick all clear all clear okay okay timately complete watching from Trend wow important concept concept basically concept atoms molecules and and chemical arithmetic a actually mole at Moes and conic struct important perod okay for minute minute 1 minute ATS molecules chemical arithmetic chemical arithmetic for 11 and wbj okay okay then only possible actually impossible atomic structure one anything thatone aad number of molecules that is 6.022 into 10^ 23 6.022 into 10^ 232 mole O2 molecu O2 mole molecular mass one molecule one Mo example single just2 Moy at this is my first question B PW wbj course 2.0 2 okay oy one2 a number of o2 molecule a number of o2 molecules one oygen at number of o2 molecules 2 into number of oxygen atoms one2 molecule number [Music] of2 number of 2 into oxygen at one mo one MO one that is at m one mass of atom one Mo that is that is okay okay one mo one MO that is mass molecular mass one Mo GP G un ion by . L ATP very important that is number of M weight by moleular weight weight weight by molecular weight not by number of particles number number of particles number volume of gas in liter divided by molar volume that is b. Char lit. lit at a div volume show act question question the largest number of molecules largest number of molecules sh at Le largest number of mules largest number of molecules 36 36 water that means H2 molecular mass H2 2 into 1 plus oxygen 16 18 g 18 G H2 number number number into a number 36 H2 H2 two M 28 g carbon that means 28 46 G ethy alcohol ethy alcohol Mone C2 H5 o ethy alcohol C2 H5 o car 2 into 12 + 5 into 1 hydrogen plus [Music] [Music] o 46 that is 1 54 G nitrogen pentoxide that is n25 N2 14 14 into plus oxygen 5 into 16 28 + 80 8 x x g n25 one that is one number of moles number of number one one option a option number of Mo small number a option A optional tiisha sjy Pima ah tumon Rani asip for important atomic mass average atomic mass by average atomic weight abundance into atomic weight divided by 100 that means percentage abundance of isotop one into Atomic one plus percentage abundance of into okay that is percentage composition percentage composition comp percentage of element percentage composition percentage composition percentage of an element in a compound number of at number of atoms into element atomic weight divided by molecular weight of the compound into 100 percentum Caron percent of calcium percentage of carbon or percentage of oxygen easy example easy example Rana hajra at please the B percentage calcium carbon are question to part percentage composition simp number of ATS into atomic weight calcium 40 divid molecular weate 40 plus Caron 12 O 3 into 16 400 weight 100 into 100 that is equals to 12% percentage oxygen equals toy atomic weight 16 total molecular weight 100 into 100 empirical formula or molecular formula empirical formula and molecular formula empirical formula and molecular formula okay 68 40 into Ron a of the clear H question percentage 4.6 54.4 formula Cate molecular formula molecular weight molecular weight of this compound n simplest whole number ratio simplest whole number ratio simplest whole number ratio EMP form formula weight by empirical formula weight EMP form EMP formula molecular formula molecular formula finally formul molecular form Mo that is 40.6 by hyen 1y 54. rest of the this percent approximately that is 3.3 something number simplest whole number ratio thank you percent henit simp number simplest whole number ratio C3 h8 32 right simp 5 3.3 3.4 3.3 something clear clear 5 by 3.3 5 by 3.3 1.5 1.5 5 5 1.5 1.5 C 1.5 1.5 3tim formula C2 H3 O2 C2 H3 o22 C2 h32 EMP form formula Cate 2 into 12 + 3 into 1 + 2 into 16 59 EMP formula weight empirical formula 59 molecular formula molecular formula some empirical formula C2 H3 O2 2 C4 h64 molecular formula of these compound easy important okay PQ chapter compl 45 45 days important you are serious for wj2 RC okay thank CH4 gas methane plus O2 com O2 gas carbon dioxide gas plus H2 normal hydrocar that is CX y plus O2 CO2 plus H2O X number y number ofren oyy 2x y by x + y 4 ultimately x + y by 4 into for 2 2x 2 y simple equation number of M number of Moes okay two mol oxygen react one Mo carbon dioxide two Mol one one 16 2 mol 2 into 1 Mo O2 1 Mo O2 Oxygen 16 G Atomic mular into carbon dioxide 44 G 1 Mo into 44 44 g carbon dioxide H2 2 2 into 18 number of molecules by avocado number number of molecules number of moles into number number of molecules into number of o2 molecules one Mo carbon dioxide number of carbon dioxide molecule 2 m H2O 2 into na number of H2 molecules one volume g l 2 2 into L Carbono 1 that is. H2 according to this chemical equation Caro H22 B equation2 of2 re H2 according to balanced chemical equation one one number of molecules into number of balanced equ Okay C Li Li very common example N2 gas plus 3 H2 gas 2 NH3 gas react rea liting reent limiting reent Rea four m 9 M Mo NH3 for for NH3 form limiting Li liting [Music] obvious am2 chicken age to limiting reent okay I you see good very good 12 but you don't have amount of H2 vegian t called limiting re liting balanced equation reaction n that means H2 limiting reent number of mes of N2 N2 N2 given Rea that is one ex Li three m H2 liting M am M H2 six M ammonia form okay okay got question question 050 Mo of bac2 is mixed with 0.20 Mo of na3 P4 the maximum number of moles of barium phosphate b342 that can be formed is B2 for B2 plus na3 P4 B3 p42 B3 p42 plus na B ini 0.5 R 0.2 Mo initial moles a given r maximum number of mes of b34 rea2 03 01 B3 B3 p42 number of M of 0.3 okay option D option D is the correct answer option D option liting liting liting clear showen Pima mini Bish gopal PR Frac fracc percent weight by weight percentage weight by volume percentage volume by volume weight weight of solute divided by weight of solution weight of Sol solute G weight of solution gam into 100 percentage weight by volume weight of solute gam divided by volume of solute in ml into 100 percentage volume by volume that is volume of solute solute in ml divided by volume of solution in ml into 100 compon that is solute solvent fraction of solvent equals to number of moles of that component solvent and number of for divided by total number of moles N2 by N1 + N2 comp number ofes that is2 divid by total number of moles N1 plus [Music] n that means X1 X2 okay mole per kg mole per K mity mole per kg so 1 kg or th000 g 1 kg or or th000 G solvent solute dissolve that is called M of the solution number of moles of solute present in 1 kg of solvent that is weight of solvent in kg 1 kg G is called mity okay okay mity mole per lit mole per lit that is L soltion soltion marity number of moles of solute present in, mL of solution in liter ml l ml ml normality Mo per liter normality g equivalent per liter normality g equivalent per liter to equivalent that means normality number of gram equivalent number of Gam equ equalent of solute divided by volume of solution in L volume okay chity number of moles of solute divided by volume of solution in liter right right take gr g equivalent par litv correct equivalent weight equivalent weight number of equivalent weight by equivalent weight number of mes number by molecular weight number of equivalent weight by equivalent weight equivalent weight molecular weight by n Factor normality frent but okay d solution solution water solvent but number of particles will be same solute par number of number by NA number of particles number of mes number of particles number of moles into a number a number fixed on Dil M1 volume V1 after dilution marity M2 volume V2 that means M1 V12 V after toal number of number by volume number of into number of vol all clear number of solute number mes of mixing on mix3 N1 + N2 N3 n 1 n23 fin3 final volume33 V1 volume V2 volume V3 is equals to V1 plus V3 M1 V1 + M2 V2 m 3 V3 M3 final marity M1 V1 + M2 V2 by V3 and V3 is nothing but V1 V2 question all C all clear all clear question solide solution now question Sol I see II weight chapter direct question bity of a solution obtained by mixing ml 0.5 M HCL with 250 ml of 2 m HCL 750 ml 0.5 M HCL marity of Final Solution M3 M1 V1 plus M2 V2 divided by V V1 + V2 M1 0.5 into plus M2 2 into 250 ml [Music] volume 500 divid 5 7 8 0.875 correct option a option a correct EAS Bish bab shyon ganes gaming sujit um Prasad deep Pima kushal sh Niki tonj sh goal okay class 11 and chapter 11 okay chemical Bing 1 G of a carbonate M2 CO3 on treatment with excess HCL produce 0.011 186 mole of carbon dioxide the molar mass of m2c M2 CO3 M2 CO3 on treatment with excess HCL h reaction2 of a carbonate M23 that is one G EX 0.1 0186 carbon dioxide mass of M23 in 0.186 number of weight by molecular mass molecular mass molecular weight weight by number of moles 1 given number of moles 0.186 option b 84.3 option b backl clear back Shish sh Niki m number of moles of K4 that will be needed to react with one mole of sulfite ion in acidic solution the number of moles of K4 that will be needed to react with one mole of sulfite ion in acidic solution d b a b d number of moles of K4 that will will be needed to react one mole of sulfide ion in acidic solution I3 2 minus acid solution H2 S so4 2 minus plus H2O decreas ination number un decrease in oxidation number x - 6 - 2 x x oxidation number plus that is 2 unit increase two unit increase in oxidation number two unit oxidation number increase increase decrease number 2 2 M4 minus + 5 S3 2 minus H M2 plus2 four posi negative POS clear manganes manganes Rea with one Mo suf 5 m 2 m 2 mol M4 minus one MO 2 by 2 by 5 Mo 2x 5 Mo M4 minus that means K4 option a correct option a correct option A sujit Bish sh monima sh okay structure radius Velocity energy form radius formula atomic structure r that is n² h² by 4² m z s n² h² by 4² m² Vol velocity 2 ZD s by NH 2 pi ZD s by NH energy total energy - 2 piun s² E power 4 m by n² h² velocity species one electr system hren like species hyren like that means one electron system that means one electron system one electron systemi lithium 2 3 I plus one electron lithium electon 2 plus one electron elili number nucleus nucleon Neutron protoni that me that is nothing but principal quantum number principal quantum number principal quantum number it principal quantum number 0.529 5 R1 into n² okay okay V1 E1 into z s by n² solve clear okay B that is new bar 1 by Lambda equal to R into into Z Square R constant 1 by N1 squ minus 1 by N2 s Maxim that is inite Maxim Max fix that1 fix N1 always one mintt okay 13.6 13.6 elect vol dly equation equation equ Lambda equal to H by MV Lambda = H by MV MV lamb mval NH by 2 angular momentum of electron mass m velocity v r r radius m v equal to NH by 2 pi l l that is 2 Ral n Lambda okay number discuss quantum number quantum number quantum numbers principal quantum number cont principal Quantum principal quantum number principal quantum number quantum number that is quantum m m magnetic quantum number M magnetic quantum number r s pin quantum number pin quantum number pin quantum number L value 0 to nus1 0 to nus [Music] one Z magne quantum number M value 0 to nus Value L value 0 1 23 s p d one is one is one is oral number of oral l z that is 1 + 1 1 one 0 1 2 Sub s p 3 S PD l that isus one oneus one [Music] p p p that me - 2 -1 0 + 1 + [Music] 2x Z Dy z d x² - Y sare and DJ Square r what clear ma'am quantum number quantum number El orun bang okay l11 to+ one L - 2 -1 0 + 1 + 2 lus l l 0 + one plus Orit S2 2 S2 2 ppant number 2p number of principle HS multiplicity rule P exclusion princip very important maximim 2 - 3 plus 3 - 3 - 2 -1 0 + 1 + 2 + 3 okay principle El thatp Quant number okay n plus l r n 3D 4 1 2 [Music] 3D example exle 25 manganes atomic number 25 1 2 2 2 P6 3 S2 3 P6 1 a 2 p a 3 2en for number bre ma' no break please' but but [Music] El El [Music] 2 1 S2 22 26 32 36 okay for please b b arrange the following orbital in decreasing order of energy n plus [Music] l n plus L ru n l that is elect de option correct oh finally sujit sh orod gopal shita ah Arena kuna launi kushal and okay after experiment weight atom numberal property of element me period table okay okay perod table [Music] to right left to right left to right left to right top to bottom left to right left to right r a top to bottom top to Bott left to right decrease decreases top to bottom top to bottom increase in incre right elain enpy by electron affinity left to right increase top to bottom decrease electro negativity electro negativity left to right increase top to bottom decrease metallic character metallic character metallic character left to right to right okay boron carbon nitrogen oxygen number one 3 4 5 6 7 8 9 elect that2 2 S1 lii s 21 1 S2 2 S2 Bon 22 2p1 Carbon 2 S2 2 P2 nitrogen 2 S2 2 P3 oxy 22 2p4 22 2p5 Val elect configuration only minutes minut B they she oh join join pH eny lithium berum boron carbon nitrogen oxygen fline number El 21 1 S2 2 2 P6 32 36 41 I known as2 that is left to right sicre left to right REM to right left to right increase top to bottom iation enpy F half field configuration full field configuration stable configur fullfill configuration half completely fill configuration stable configuration electronic configuration 21 rem2 2p3 oxygen 22 2p4 nitr 23x elig REM elect electron aity electron aity electron gain enthalpy electron gain enpy e [Music] iation that is known as electron gain enpy left to right electron gain eny increase Maxim El example Florine chlorine bromine IOD General elect El negative energy release El R 3p 2p R 3p 2p size small Elion okay okay lanite sonon negative and nucle positive number number nuclear Z minus Sigma Sigma is scening constant nucle s than P great than D greater than f d f electrons contra C how many moles of electrons will weigh 1 kilogram B one elect mass of one electron mass of one electron that is 9108 into 10 ^ - 31 kg one mole electron mass mass of 1 mole electron that is one mole electron 9108 into 103 1 into one mo one 6.022 into 10^ 23 electron 9108 into 10^ - 31 into 6.022 into 23 at 9108 into 10^ - 31 into 9108 8 into 6.022 into 10^ minus 8 kg kg 1 Mo 9108 into 6.022 into 10us 8 one 1 / 9108 into 6.022 into 10^ - 8.2 1 by 9108 into 6.022 10^ 8 option D okay next question option option all start Colum this take got got well for 5 ml 0.1 M pb3 H2 is mixed with 10 mL 0.202 molar Ki the amount of pb2 precipitated PB n32 plus a i PB I2 precipitate vol 01 10 mL 10 mL 10 mL 0.02 into 10,000 Li rea re 2 1^ minus 4 mole pb2 power so the amount of pb2 precipitated 10^ minus 4 Mo simple question number into volume number of moles by volume number of moles marity into volume marity into volume vol liting 1 10us 4 option b is the correct yes okay okay option b correct option b D electronal angular momentum calate orbital angular momentum cun L into L + 1 into H by 2 root over L into L + 1 into H by 2 Pi root over L into L + 1 into H by 2 pi B fell B fell chot B fell comment repeat 1 2 3 s p [Music] d 2 + 1 2 otk 6 h by 2 pi option a correct option A correct option a correct the correct set of quantum numbers for the unpaired electron of chlorine atom chlorine atom correct set of unpaired electron of chlorine atom chorine 1 32 3p5 unpaired electron of chlorine UNP El this is one El that means l so option C atomic iic radius increasing I radius increasing ionic radius is electronic species number of electron ionic radius spe radi increasing order number of ELR elect number number increase elect number a correct a a last question the first electron affinity of carbon nitrogen and oxygen will be of the order electron affinity order electron affinity order electron affinity order vol spe b b b carbon nitrogen oxygen General left to right nigur niten elect nitrogen option option b correct okay all C final leader final leader students participated 64 gopal kall Shion mahj ahand dead showman Dragon Joo orip sh Chon subit GES Nikki PR laboni babai beep Dei Min sh rupam monik Deitra Arena visha Rani ahed obij shok orita Universal Academy aushi subo onim b rupam u oani Joy mahib Toto laki riat or M andir thank you so much okay okay thank you

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Length: 192min 55sec (11575 seconds)

Published: Thu Mar 07 2024