Mechanical Properties of Solids in One Shot | Class 11 | JEE 2024-25 | KRD Mam

hello everybody Welcome to V channel are you ready so are you all ready for's session Live start good evening everybody hope Live start yes good evening preparation 24 25 good evening everybody good evening shik Hussein yes good evening so suar good evening Abu Luna first class with you ma'am nice to see you ma'am Luna first class thank you for the compliment but good evening let us start our today's class water bottle yes yes anyway let us start Super Why is this not starting ofid the biggest scholar Mega vant scholarship test okay so scholarship test admission test so December 2 3 9th 10th class nth class 10th class inter first year second year droppers anday examination so top rank 5 Day program with a space Research Center five days stage drones drones smartes tesc and the most important Point registration completely free so most important point to be told so mechanical properties of solids most important okay most important discussion so stra modul of elasticity mod of elasticity okay so elastic body and plastic body okay deing restoring force deforming force restoring Force restoring force deforming force and already completed last rision so deforming Force for shape the force which brings a body shape or size Force which changes a force which changes shape or of a body restoring for deforming exing R greater than r r less than r r greater for so restoring forceing de restoring Force after the removal of deforming DC which is better both are important okay so elastic plasticas external deform okay so elastic material perfectly elastic material example quads quads Diamond so q a r t quads Diamond the best example qus best example for elastic material elastic material yes it is elastic material am of restoring for so clay examples of plastic material perfectly elastic perfectly plastic Mater coming to the distance what happen for distance gra there is a straight line so for distance po potential energy distance [Music] Librium distance equilibrium distance and r next e r less than r r less than r f so tun student of K I already wished you and once again happy birthday so R less than positive negative DX very good super minimum potential energy minimum unali yes lavakumar super correct negative me attractive very good attractive means oh very good attractive means very good important point to Beed formula restoring Force stress correct definition restoring Force by unit area stress correct definition restoring Force per unit are deforming Force so simple stress is equal to force by area this is the formula stress is equal to force by area next stra change in dimension change in dimension by original Dimensions so Dimensions original Dimensions so di vol lse shape are shape volume shape stress longitudinal stress then next surface superficial or area superficial and area superficial superficial stress Vol next sharing or tangential stress tangential or shearing sharing ma'am M Class ma'am hu gaming stay tuned so longitudinal stress longitudinal stress buk stresses Force acts Force acts perpendicular to surface importantes for Force acts along the surface along the surface same longitudinal longitudinal strain buk strain shearing strain bu strain and shearing stra hooks law what does hooks law says according to hooks law H within elastic limit St stress strain curve important four mark question 2 A B C point elas limit o to a elastic limit a to c hooks obey so a to c Ying limit breaking elas limit stress is directly proportional to strain stress is directly proportional to strain Le stress by strain is a [Music] constant of [Music] elasticity modulus of elasticity stress by strain is a constant that in a modulus El Point breaking stress okay so breaking stress breaking stressing maximum breaking so breaking breaking stress is equal to breaking force by area B breaking BF breaking force breaking Force by area so by area important formula not only tet to Breaking stress equal simp breaking stress equal to breaking force by area breaking force is equal to Breaking stress into area breaking stress into area crosssection depa of crosssection dep for example situ breaking maction important very very simple right the area of crosssection of July 26 the area of crosssection of rope used to lift a load by crane is area of cross-section area of crosssection the maximum lifting capacity of the crane is 10 metric tons the increase to increase the lifting capacity of crane to 25 metric tons 25 metric tons maximum load Max first of all given information area 2.5 into 10^ minus 4 M Square breaking force 25 M area of crosssection of the Rope should be rope area of crosssection formula breaking stress is equal to Breaking so breaking stress and force by area breaking stress low Force by area breaking stress low Force 10 metric T by area 2.5 into 10 power minus 4 is equal to breaking force 25 Force so breaking force so that's it 2 Time 5 five 125 so 125 into 5 25 * 125 into 2 so area is equal to area is equal to 5 into 2.5 into 10 powerus 4 by 2 Sorry by two so by 6.2 6.2 10th class electricity so 10 CL okay so breaking clear go let's start modul of elasticity modul of elasticity modulus of elasticity modulus of elasticity is nothing but stress by strain us mod elasticity mod of elasticity okay young modul so modal L okay modul next shearing y symb modulus b or k symb shearing modulus or capital letter G shearing modulus or capital letter g y formula stress by strain so YY longitudinal stress longitudinal stress by longitudinal strain lengthwise longitudinal strain longitudinal stress by longitudinal strain bu volume wise so volume stress by volume strain volume stress by volume strain okay volume stress by volume strain it and sharing strain so tangential Force per area by strain tangential stress [Music] tangential sharing shearing strain shearar stra LPR com com Bas okay so tensile stress formula tensile or compressive tensile or compressive longitudal stress longitudinal stress lse stress by longitudinal stress force by next very good buk stress buk stress volume wise stress buess exid Force normal peress by same with shearing stress also shearing stress shearing stress formula Force by area stra strain formula change in dimension by original Dimension lengthwise change Delta L by L volume change St Delta sharing theface tan Theta is equal to opposite side by adjacent side Delta X by L simple Theta is equal to Del X is approximately equ Al formula young modulus longitudinal stress by longitudinal strain equal by a into Del L because highest volume of questions formul so y equal by a into Delta L fix next bulk modulus bulk stress force by area by buk volume Delta V by V change in volume Force by P by Del V by v p v by Del vti stress force by are Del X by Del F by a into thet Delta X by L that's it I law okay so young modul bu modul andity reciprocal of bulk modulus is called compressibility reciprocal reciprocal of B is called reciprocal of B is called [Music] compral 1 by Capital compressibility find out compressibility reciprocal of BU modul mod sharing breaking for breaking force key difference breaking force key breaking force key difference important point modul of elasticity mod elasticity modulus of elasticity y b do not do not depend on do not depend on dimensions of material dimensions of material depends on depends on nature of of material material material e [Music] young modul you just remember as young modulus young modulus and okay next hi anyway M Class gaming so okay mod mod of elasticity ofid application when a wire when a wire elongates when a wire elongates due to its own weight its own weight that initial initial length initial L elongation Elation El crosssection of wire area of crosssection of wire of crosssection crosssection s a Del mg can I write tension of motion body di so is equal to tension into L by a into Delta l original length of the wi original length of the wire L okay first year questions question same so that's it same to same so yal toity gravity mg w w 2 Del W okay 97 98 moving on to next application next application analogy of analogy of Rod as spring roding analysis so formula spring Force formula KX okay Force formula force yal a into Delta l f is equal to y a Delta L by L okay by L equal to KX X elongation in Spring X Elation in Spring Del Del Elation X elongation so Del l X compare on comparison very good select on comparison on comparison can I write K is equal to y a by l k is equal to y a by L analysis okay analysis short notes 25 have you understood Young's modulus constant area of cross-section constant next application rods in series parall combination next application important combination combination of of rods combination [Music] of but yes so starting with series combination to start series com combination of rods combin super no problem at all but yes so so first mod y1 mod Y L1 l l series combination the elongation produced the elongation produced is different the elongation produced is different in different wires different in different wires wires Elation restoring Force restoring Force restoring Force restoring Force restoring force is nothing but mg because restoring restoring for is same for both wires for both wires R wires key restoring so Elation delation Del total elongation equal to Delta l1+ Delta L2 total elongation is equal to Delta L Del Del formul Del L formula yal L by a into Delta L Delta is equal to Delta L is equal to f l by a y okay Delta L is equal to f l by a y Del L1 so F L and T L1 by a by y1 plus F into L2 by a into Y2 overall elongation overall elongation overall elongation comall combin overall combin overall combin L1 L2 Del overall elongation so overall elong key overall force same overall length L1 + L2 by overall area same overall elongation overall overall F by a f by a f by a canc L1 + L2 by y effective isal to L1 by y1 + L2 by Y2 formula if L1 L2 soal 1 by y1 + 1 by Y2 y effective equal 2 y1 Y2 by y1 + Y2 spr EAS easy anyways so have you understood series combination shall we move on to parallel combination 9:00 nextall combination parall combination of rods wires par combination combin combin mod y1 of crosssection okay L1 okay same combin combin combin combin combin the elongation the elongation produced the elongation produced in both wires the elongation produced in both wires is same restoring forces spelling B very good restoring forces restoring forces are differental restoring Force so total restoring Force f is equal to fub1 + FS2 total restoring Force F1 elongation produc same so Del L1 equal Del l2b same restoring Force parall combination same elongation so total restoring force equal F1 F2 Elation a y so could fub1 l fub1 l by A1 into y1 is equal to F2 L by A2 into Y2 problem Delta L by L A1 y1 Delta L by same Delta L by L is equal to uh plus A2 Y2 Delta L by Lal total F area of crosssection A1 + A2 into y effective into Delta L by L so Delta L by l cancel A1 + A2 into y effective is equal to A1 y1 + A2 Y2 parall combination so if A1 equal A2 isal to a 2 y effective equal y1 + Y2 by 2 2 y1 Y2 by y1 + Y2 y1 + Y2 by 2 so series combination parall combination problem okay highly repeated highly repeated question the the elongation okay the elongation the length of the wire the length of a wire length of a wire is L1 when tension T1 is acting on it next the length of the length of same wire the length of same wire is L2 when tension T2 is acting T1 L2 find question find original length of wire find original length of WI right tension T1 so yal four1 initial length original length of the let this be L initial l l initial L con initial constant so T1 L by crosssection L1 Del L1 final lus original Linus L L1 initial length l T1 L1 Elation final length minus ini next modul equal to tension T2 initial length L by area of crosssection final length L2 elongation L2 minus l L2 e y e y same y y y same so equ T1 L by a into L1 - L is equal to T2 L by a into L2 - L so T1 into L2 - Lal T2 into L1 - L T1 L2 - T1 L equal to T2 L1 minus t T2 L1 - T2 l so L2 L1 T1 L2 so L KN is equal to uh T2 L1 - T1 L2 by T2 minus [Music] T1 answer question answer Lal T2 2 L1 minus T1 L2 reverse T1 L2 minus T2 L1 T1 minus T2 T2 L1 minus T1 L2 T2 minus T1 T2 T2 T1 T same July 2021 July 2021 uh February 2021 July afternoon july4 2023 direct L1 T2 minus L2 T1 T2 T2 this is the correct answer T1 L2 minus T2 L1 by T12 T1 L1 next wrong T1 T2 wrong T2 T2 correct CH okay question 21 21 21 21 at the same time as it same it repe as it answer answer find out homework question homework question the when when a force of when a force of 4 Newton acts length of wire the the length of the V and very good the length of wire is L1 okay next when a force of force of 5 Newton acts length of wire length of wire is L2 then find the length find the length when 9 Newton acts same model same model let us move on to the next model next wires wires color situ okay y mod Y2 okay the weight the weight w weight w at what distance wire a the wire B at what distance at what distance from wire a the weight the weight w must be must be hanged so that so that the stress produced the stress produced remains same in Remains the Same for both wires remains same for both wires same prod is this class you will be there after for this class okay sorry for that so so toal okay remain stress inre a must be equal to stress in wire B so stress in force by area foror pleas so stral L okay Y into Delta L by L y1 A into Delta L combination Delta L1 by L is equal to Y2 a Delta L2 by L L2 and a L2 and L1 a L2 and B A cancel a by L A by L so y1 Delta L A is equal to Y2 Delta lb so y1 by Y2 is equal to Delta lb by Del L produced in a equation number one next principle of moments principle of moments principle of moments per torque on left side clockwise is equal to torque on anticlockwise Tor in clockwise is equal to torque in anticlockwise system of particles how many questions from this chapter one question one question but one question so Tor in clockwise is equal to torque in anticlockwise Tor formula Force into perpendicular distance Force the perpendicular distance okay Force sorry Force T2 okay so T1 into X T1 t a a b t a TB t a by X is equal to TB by TB by lus X TB by l x okay stress in a stress in b meth method T A by A is equal to T B by area of a area of B equ next next let us take an example okay y1 is equal to M1 g into L by a into Delta L low okay so so sorry sorry oh wait wait wait1 M2 into G M2 g into L by a Del okay when a wire is rotated simple four Place M Omega squ four place M v² by r yal f l by a into Delta L form into 1 minus density of liquid by density of solid mechanical properties of fluids so next last uh strain energy strain stra work stored in the form of strain energy strain energy direct formula energy per unit volume equal half into stress into strain basic formula energy by volume is equal half into stress into streng only energy find out Vol only enery stress Square stress Square by y Le half into y by strain Square stress next poison ratio poon ratio poon Sigma is equal to lateral strain thank you so much guys for your response lateral strain by longitudinal strain longitudinal lengthwise longitudinal lengthwise lateral sidewise I'm doing good thank you okay so poison ratio is equal to minus Delta d by D by Delta L by L diameter L length I two marks [Music] note practical theoretical value th e o r e t i c a l theoretical value of Sigma minus one in 0.5 practical value practical value one0 0 0.5 0 chemistry physics chemistry arum Nani okay solid question start first question answer first question answer the length of wire is made Double Radius is half its respective values double so can I write can I write y Das is equal to F into 2 L by IUN into R by 2 whole s Delta l r by 4 2 are 8 y Das is equal to 8 y can I write eight times option b correct yes yes correct answer option one correct totally wrong young modulus option one correct young modul it will not depend on length and area of cross-section [Music] start option two option one option one young modulus will not depend on length area of crosssection okay next the force required to stretch a wire of cross-section area cross-section area double its length will be double its length area and 1 cm square 4 M squ to double its length L1 L1 2 lus L L Del l reir F find out modul 2 into 10^ 11 per m squ f FAL y a Delta L by L Delta L Del L A 2 into 10^ 7 option D three three D three option three next steel wire of length AEL young mod steel connect to end connected end to end series combination end to end series comination a nation series combination when and stretched by a load same loation is found to be load app. combin Del Lal Del L1 Del l2a by Y into a force find out applied find Lo app into L 3.2 by area of crosssectional A2 is = PK into 1.4 into 10 power - 3 whole s a into uh f l by a into Delta l y so 2 into 10^ 11 plus F into 3.2 so 3.2 F into the L 4.4 4.4 by a into Young's modulus 1.1 into 10^ 1.4 Del 1.4 3.14 into 1.4 into 10us 3 S value find out do it as homework pi value 22 by 7 22 by 7 is 0.2 okay 22 3.4 22 by 7 7 0.2 * caning from Pixel support length changed to L1 and L2 when 1 kg 2 kg are acting 1 kg act length L1 2 kg length L2 okay length L2 suspended masses respectively from pre the value of L is equal to value of L 2 L1 L 2 L1 L2 Lal T2 L1 minus uh T1 L2 by T2 - T1 T1 M so Mass into g 1 into 10 Newton T1 10 Newton T2 2 into 10 20 Newton sub important the value of G is taken to be 9.8 without any significant error his observations are as following fractional error in the measurement fractional error units and measurements units and measurements Delta y by yal Delta M by M plus Delta g g constant Delta Gant Delta G by G 3 into Delta L by L plus Delta B by B plus d Cube and 3 into Delta d by D 3 into Delta d by D plus Delta Delta by Delta Del Delta M Delta L Delta B Delta D Delta Delta m l b d Delta just substitution so ma'am did gam left V reply yes gutam s left vantu because he got seat in IIM Indian Institute of Management Jad games Jad games now is not in teaching field at Alles this is the answer for you so have you understood 21 Easy 2 y1 Y2 by y1+ combination series combination parall combination 2019 okay so thank you all keep going next j class super class theal scage calers and SC next coming up M Unstoppable Point Motion in a PL start get ready let's

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Length: 94min 27sec (5667 seconds)

Published: Fri Nov 17 2023