You know what can be kind of peculiar and
surprising? The fact that, whenever you want to shoot outside, everyone decides to mow their lawn. You know what else can be kind of peculiar
and surprising? Water. And in the right circumstances, I could even take water that’s flowing down and spurt it straight up. How? All of these things are possible, thanks to
the study of the flow of fluids, known as Fluid Dynamics. [Theme Music] By now, you’ve picked up on the fact that
-- even though we live in the physical universe -- describing the rules of the universe sometimes requires us to pretend that certain things aren’t happening. Like the time we rolled a bunch of stuff down
a ramp, and pretended that there was no kinetic friction. The same is true when we talk about fluids. Because, fluids in motion are dynamic and there are many, many things going on in and around them all at once. So, in order to grasp the essentials of fluid
dynamics, let’s just do some pretending, shall we? For one thing, we’re going to consider the
fluids in our examples to be incompressible, meaning that their densities won’t change. We’re also going to assume that fluids flow
perfectly smoothly, and have no viscosity. You’ve probably heard of viscosity before: When a fluid flows easily, like water, we say that it has a low viscosity. Fluids that don’t flow as easily, like honey, have a higher viscosity. And much like kinetic friction does in moving objects, viscosity tends to complicate things in moving fluids, which is why we’re generally going to pretend that the fluids we’re studying don’t have any. Now, say you have some water -- which exists
under all of these hypothetical conditions -- in a pipe, moving along smoothly. This pipe narrows about halfway through, so
that one end is narrower than the other. This shape is going to affect some of the
properties of the water’s flow, as it passes through the narrower side of the pipe compared to the wider side. But one thing that won't change is the mass of water that’s moving through any given area in the pipe over time. This is called the mass flow rate, and it’s
always going to be the same everywhere in the pipe. That’s just because, as the water flows through the pipe, it pushes along the water in the rest of the pipe, too. So if one part of the pipe has, say, a kilogram
of water moving through it every second, the rest of the pipe ALSO has to have a kilogram
of water moving through it every second. This fact, that the mass flow rate at one point in the pipe will be equal to the mass flow rate at any other point, is called the equation of continuity. And it can tell you a lot about the relationship between the velocity of a fluid and the cross-sectional area of the pipe that it’s flowing through. Let’s say you’re an engineer for the Water
Department of Hypothetical City, and you need to understand the mass flow rate of hypothetical water that’s going through a certain point in your underground pipe system. But you don’t know the mass that’s going through that part of the pipe at any given moment. All you know are the water’s velocity and the area of the cross-section of that certain section of pipe. In order to describe the mass flow rate, you’ll
have to use what we know about density, area, and velocity to work some algebra magic: First, let’s have a look at a cross section
of that point of the pipe. From our last lesson, you know that the mass of the fluid moving past this cross-sectional area, over time, is equal to its density,
times its volume. And, the volume of the fluid moving past this point is simply the area of the pipe at this cross section, times the distance the fluid
moves. And! From our episodes on the physics of motion,
you also know that the distance the fluid moves, divided by the change in time, is equal
to the fluid’s velocity. So, by putting all that together, you can
get a different version of the equation of continuity: At any given point in the pipe, the density
of the fluid flowing through it, times the area of the pipe, times the fluid’s velocity, will be the same as for any other point in the pipe. And since you’re dealing with an incompressible fluid, the density is going to be the same for every point in the pipe anyway. So really, you’ve just figured out that
at any point in the pipe, the area of the pipe times the fluid’s velocity will be
the same as for any other point. It’s the same thing we said before: The mass
flow rate is the same for every point in the pipe. But instead of putting that relationship
in terms of mass and time, you’re putting it in terms of area and velocity. And, in your role as a water-department engineer,
this is important for you to know! Because it means that, where the pipe is narrower,
the fluid will have to flow faster, in order to compensate. But here’s a weird thing: A fluid that’s flowing really fast actually has less pressure than when it’s flowing more slowly. Sure, it might feel like it’s exerting more
force than when it flows through a wider opening. But that’s not what physicists mean when
they talk about the pressure in a pipe. They’re really talking about the pressure
on the walls of the pipe. This means that, the slower the fluid flows,
the more pressure it puts on the pipe itself. This is known as Bernoulli’s principle. It states that the higher a fluid’s velocity
is through a pipe, the lower the pressure on the pipe’s walls,
and vice versa. Bernoulli also came up with what we now know
as Bernoulli’s equation. It might look kind of intimidating at first. But when you break it down, it’s actually just a way of combining a bunch of things that you’ve already learned. Bernoulli based his equation on the
concept of conservation of energy: as a fluid flows through a pipe, it won’t gain or lose any energy. This means that, no matter where
the fluid is in the pipe, if you take all of the forms of energy that the fluid has at that point and add them up, they’ll equal the same number
as any other point in the pipe. To better understand this, have a look at how the three forms of energy in a fluid are represented in Bernoulli’s equation: First, there’s pressure times volume. In our episode on work and energy, we defined
energy as the ability to do work. And when a fluid applies pressure and moves
the volume of fluid that’s downstream, it’s doing work. So, pressure times volume must be a form of
energy. The first term in Bernoulli’s equation takes
that energy, and divides it by volume. Which just leaves pressure. Next, a flowing fluid also has kinetic energy. When we first talked about kinetic energy, we said that it’s equal to half of an object’s mass, times its velocity squared. Again, Bernoulli divided this form of energy by volume, to get half the fluid’s density, times its velocity squared. That’s called the kinetic energy density,
and it’s the second term of Bernoulli’s equation. Finally, a flowing fluid also has the potential
energy that comes from gravity. And we’ve said before that the potential
energy from gravity is equal to an object’s mass, times small g, times its height. When Bernoulli divided that by volume, he
got density times small g times height -- the potential energy density,
and the third term of his equation. Why divide all these terms by volume? Well, when it comes to fluids, it’s just easier to talk about things in terms of density than it is to talk about mass. So when you look at his equation piece by
piece, you can see that Bernoulli was really just putting conservation of energy into a
special form that would be useful for fluids. Now, let’s look at a special case of Bernoulli’s
equation, known as Torricelli’s theorem. Torricelli’s theorem uses conservation of energy to find the velocity of fluid flowing from a small spout in a container. And it says that the velocity of the fluid
coming out of the spout is the same as the velocity of a single droplet of fluid that
falls from the height of the surface of the fluid in the container. In other words, the pressure that’s pushing
the fluid out of the spout gives it the same velocity that it would get from the force of gravity. To see this theorem in action, let’s say you’re not a water department engineer -- you’re just YOU, and you’re watering your garden
with the water you’ve saved up in your rain barrel. Your barrel doesn’t have a top, and you’re
watering your carrots and lettuce and stuff from a hole -- or a spout -- in the side. Now: You want to know: What’s the velocity
of the water coming out of the spout? From Bernoulli’s equation, we know that
the sum of the pressure, kinetic energy density, and the potential energy density of the water
at the TOP of the cooler, will equal the sum of those three qualities of the water coming
out of the spout. But we can simplify that relationship a bit,
to find the velocity of the fluid coming out. First, the upper surface of
the water in the barrel, and the water that’s coming out of the spout, are both exposed to the atmosphere. So the pressure at those points will be the same -- it’s just the atmospheric pressure. So we can cross off the pressure from each
side of the equation. Now, there might be water coming out of the spout, but the top of the barrel has a much bigger area. So the water at the top of the barrel isn’t
going to be moving very much. In fact, we can say that its velocity is basically zero. Which means that the kinetic energy density
for the water at the top of the barrel is zero. Finally, we can cross out the density in each
term of the equation, since it’s not changing. We’re left with a much simpler equation,
with only three terms -- an equation that should look VERY familiar, if you’ve watched our episodes on the physics of motion. It’s a kinematic equation! You already know the two main kinematic equations:
the definition of acceleration and the displacement curve. And you can rearrange them to get another
equation that relates displacement, velocity, and acceleration -- without considering time. It’s exactly the same equation as the one
we just found by using Bernoulli’s equation to describe the velocity of the water coming
out of the spout. So, Torricelli’s theorem tells you that if a droplet of water fell from the same height as the top of the barrel, when it reached the level of the spout, it’d have the same velocity as the water coming out of the spout. Now you know how fast the water’s
coming out your rain barrel, and how much water you’re putting in your garden over a certain amount of time. But you want to try something fun? Let’s turn the spout on your barrel so it’s pointing up instead of down. If the water from this spout could shoot straight up, the stream would get exactly as high as the water at the top of the barrel, before falling down to the ground. Today, you learned about fluids in motion,
with a focus on the continuity equation, Bernoulli’s equation, and Torricelli’s theorem. You also learned that lawn mowers are loud. Crash Course Physics is produced in
association with PBS Digital Studios. You can head over to their channel to check out amazing shows like BBQ With Franklin, PBS Off Book, and The Art Assignment. This episode of Crash Course was filmed in
the Doctor Cheryl C. Kinney Crash Course Studio with the help of these amazing people and
our equally amazing graphics team is Thought Cafe.
As a chemical engineer, I really do not like their description of how pressure relates to velocity via Bernoulli's principle because it is SUPER misleading. Just because a pipe is at low pressure doesn't mean that the velocity in the pipe is high. The only way this is true is if you are comparing the condition at one point in the pipe to conditions at another point in the pipe. The way it was stated and shown in the video makes it look like you could have two unrelated pipes and just by having them at different pressures you could have different flows. Bernoulli's principle is much easier to understand if you talk about how the change in pressure relates to the change in velocity, height, and cross sectional area.